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Vladimir79 [104]
3 years ago
14

I need help with question 13pleaseee im struggling

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0

You could create a equation such below:

y= 50x+20

Next, put 12 in both y=50x+20 and y=15x+80

Then, y=50x+20=50 · 12+ 20=600+20= 620

           y=15x+80=15 · 12+ 80=180+80= 260

 

Compare these two, it's clearly that the second one is cheaper


Answer: The camera in the second store is cheaper.

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