Answer:
x = -48
Step-by-step explanation:
-4(7.5x - 8) = -5(6.3x + 8)
-30x + 32 = -31.5x - 40
-30x + 31.5x = -40 - 32
1.5x = -72
x = -72/(1.5)
x = -48
Answer:
Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.
Step-by-step explanation:
We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.
The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.
Let X = <u><em>numbers of seals observed</em></u>
The z score probability distribution for normal distribution is given by;
Z =
~ N(0,1)
where,
= population mean numbers of seals = 73
= standard deviation = 14.1
Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X
50 seals)
P(X
50) = P(
) = P(Z
-1.63) = 1 - P(Z < 1.63)
= 1 - 0.94845 = <u>0.0516</u>
The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.
I think is a because if you see and do it you could see
Answer:
Step-by-step explanation:
Formula to be used,
A = 
Here, A = Final amount
P = Principal amount
r = rate of interest
n = Number of compounding (In a year)
t = Duration of investment (In years)
Question (5)
P = $4250
r = 0.015
n = 4
t = 3 years
A = 
A = 
A = $4445.24
Part (C)
1). P = $6000
r = 0.03
n = 2
t = 10 years
A = 
= 
= $8081.13
2). P = $9000
r = 0.05
n = 2
t = 8 years
A = 
= 
= $13360.55
Answer:
its the second one
Step-by-step explanation: