Answer:
The encoding algorithm looks for pairs of characters that appear in the string more than once and replaces each instance of that pair with a corresponding character that does not appear in the string. ... Byte pair encoding is an example of a lossy transformation because it discards some of the data in the original string.
Explanation:
hope it helps!!
Answer:
Explanation:
#include <iostream>
using namespace std;
int main ()
{
int responses[30],count[6];
int score = 0;
string resp = " ";
for (int i = 0; i < 30; i++)
{
responses[i] = 0;
}
for (int i = 0; i < 6; i++)
{
count[i,1]=0;
count[i,2]=0;
count[i,0]=0;
}
while ((resp != "Y") && (resp != "y"))
{
for (int i = 0; i < 30; i++)
{
while ((score > 5) || (score < 1))
{
cout << "Student " << (i+1)<< " please enter a value (1-5):";
cin >> score;
}
responses[i] = score;
if((score > 5)||(score<1))
{
if(score==1) count[1]++;
if(score==2) count[2]++;
if(score==3) count[3]++;
if(score==4) count[4]++;
if(score==5) count[5]++;
}
score = 0;
}
cout<< "Response Frequency Percentage"<<endl;;
cout<< " 1 "<<count[1]<<" "<<(count[1]/30)<<"%"<<endl;
cout<< " 2 "<<count[2]<<" "<<(count[2]/30)<<"%"<<endl;
cout<< " 3 "<<count[3]<<" "<<(count[3]/30)<<"%"<<endl;
cout<< " 4 "<<count[4]<<" "<<(count[4]/30)<<"%"<<endl;
cout<< " 5 "<<count[5]<<" "<<(count[5]/30)<<"%"<<endl;
cout<< "Do you want to exit? Press Y to exit any other key to continue: ";
cin>> resp;
}
return 0;
}
Answer:
a) the Statement is Invalid
b) the Statement is Invalid
Explanation:
a)
lets Consider, s: student of my class
A(x): Getting an A
Let b: john
I have a student in my class who is getting ab A: Зs, A(s)
John need not be the student i.e b ≠ s could be true
Hence ¬A(b) could be true and the given statement is invalid
b)
Lets Consider G: girl scout
C: selling 50 boxes of cookies
P: getting prize
s: Suzy
Now every girl scout who sells at least 50 boxes of cookies will get a prize: ∀x ∈ G, C(x) -> P(x)
Suzy, a girl scout, got a prize: s ∈ G, P(s)
since P(s) is true, C(s) need not be true
Main Reason: false → true is also true
Therefore the Statement is Invalid
