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chubhunter [2.5K]
3 years ago
5

Q:- You may have heard through various media of an animal alleged to be the hybrid of a rabbit and a cat. Given that cat (Felis

domestica) has a diploid chromosomes number of 38 and a rabbit (Oryctologus cuniculus) has a diploid chromosomes number of 44, What would be the expected chromosomes number in the somatic tissues of this alleged hybrid?
Biology
1 answer:
weeeeeb [17]3 years ago
6 0

Answer:

41 chromosomes

Explanation:

Cats have a dipoid chromosome number of 38, <u>so their gametes will have half that number: an haploid number of 19 chromosomes</u>.

Rabbits have a dipoid chromosome number of 44, <u>so their gametes will have an haploid number of 22 chromosomes</u>.

When a cat gamete (n=19) joins with a rabbit gamete (n=22) to form the hybrid zygote, it will have 19+22=41 chromosomes. When it undergoes mitotic division, all its somatic cells will have 41 chromosomes.

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If acetyl-CoA is labeled with 14C at its methyl group, how many rounds of the cycle are required before 14CO2 is released?
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Answer:

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<u>Complete question goes like this</u>, "<em>The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If acetyl-CoA is labeled with 14C at the carbonyl carbon, how many rounds of the cycle are required before 14CO2 is released?</em>"

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  • Succinate converts into fumarate. Fumarate converts into malate, and malate converts into oxaloacetate. Because succinate is symmetrical, the oxaloacetate can have the label at C1 or C4.
  • When these condense with acetyl-CoA to begin the second round of the cycle, both of these carbons are discharged as CO2 during the isocitrate dehydrogenase and alpha-ketoglutarate dehydrogenase reactions (formation of alpha-ketoglutarate and succinyl-CoA respectively).

Hence, 14 CO₂ will be released in the second turn of the cycle.

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