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rodikova [14]
3 years ago
14

Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual hou

sehold income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.
Mathematics
1 answer:
lora16 [44]3 years ago
5 0

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

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See question in screenshot below.
alexgriva [62]

The equation of the transformation of the exponential function <em>y</em> = 2ˣ in the form <em>y</em> = A·2ˣ + k, obtained from the simultaneous found using the points on the graph is <em>y</em> = (-2)·2ˣ + 3

<h3>What is an exponential equation?</h3>

An exponential equation is an equation that has exponents that consists of variables.

The given equation is <em>y</em> = 2ˣ

The equation for the transformation is; <em>y</em> = A·2ˣ + k

The points on the graphs are;

(0, 1), (1, -1) and (2, -5)

Plugging the <em>x </em>and <em>y</em>-values to find the value <em>A</em> and <em>k</em> gives  the following simultaneous equations;

When <em>x</em> = 0, <em>y</em> = 1, therefore;

1 = A·2⁰ + k = A + k

1 = A + k...(1)

When <em>x</em> = 1, <em>y</em> = -1, which gives;

-1 = A·2¹ + k

-1 = 2·A + k...(2)

Subtracting equation (1) from equation (2) gives;

-1 - 1 = 2·A - A + k - k

-2 = A

1 = A + k, therefore;

1 = -2 + k

k = 2 + 1 = 3

k = 3

Which gives;

y = -2·2ˣ + 3 = 3 - 2·2ˣ

Learn more about the solutions to simultaneous equations here:

brainly.com/question/26310043

#SPJ1

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