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ratelena [41]
4 years ago
6

In baseball, the pitcher's mound is 60.5 feet from home plate. If the fastest pitch ever recorded in Major League Baseball was 1

05.1 miles per hour, how many seconds did it take for the ball to travel from the pitcher's mound to home plate? Round the answer to the nearest tenth.
Mathematics
2 answers:
anastassius [24]4 years ago
5 0

Answer:

t = 0.4

Step-by-step explanation:

(

1 hour

105.1 miles

)(

1 mile

5280 feet

)(

60 minutes

1 hour

)(

60 seconds

1 minute

)(60.5 feet) ≈ 0.4 seconds

Levart [38]4 years ago
4 0

Answer:

t=0.4 sec

Step-by-step explanation:

Remember that

1 mile=5,280 feet

1 hour=3,600 seconds

Let

s -----> the speed in ft/sec

d ----> the distance in ft

t -----> the time in sec

s=d/t

Solve for t

t=d/s

step 1

Convert  miles/hour to ft/sec

105.1 mi/h=105.1(5,280/3,600)=154.15 ft/sec

step 2

Find the time

t=d/s

we have

s=154.15 ft/sec

d=60.5 ft

substitute

t=60.5/154.15

t=0.4 sec

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