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Ray Of Light [21]
3 years ago
14

A) draw the image of PQR after a 180 about the origin. Label the image P'Q'R

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
3 0

<u>Solution-</u>

1- When rotating a figure 180 degrees around the origin (As it does not matter whether you move clockwise or counter-clockwise), we apply the rule (x, y) → (-x, -y).

Co-ordinates of the vertices,

P = (1, -1)

Q = (3, -2)

R = (3, -4)

And then calculating the co-ordinates of P', Q', R'

P' = (-1, 1)

Q' = (-3, 2)

R' = (-3, 4)


2- When reflecting a figure across X-axis, we apply the rule (x, y) → (x, -y).

Co-ordinates of the vertices,

P' = (-1, 1)

Q' = (-3, 2)

R' = (-3, 4)

And then calculating the co-ordinates of P'', Q'', R''

P'' = (-1, -1)

Q'' = (-3, -2)

R'' = (-3, -4)

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Given,

  • HK is the perpendicular bisector of GJ. So, <u>GK = KJ</u>.
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_______________

Find KJ .

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First find the value of x

\sf \: GK \:  = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x =  - 15 - 10 \\ \sf - x =  - 25 \\  \sf \: -  >   \boxed{\bf \: x = 25}

Now, find the value of KJ.

\sf3x - 15 \\  \sf= 3(25) - 15 \\  \sf=7 5 - 15 \\     = \boxed{\bf \: 60}

-> The value of KJ is <u>6</u><u>0</u><u>.</u>

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Hope it helps.

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