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Tcecarenko [31]
3 years ago
8

-8=32-5qhow would I solve this

Mathematics
1 answer:
Alex3 years ago
6 0

-8=32-5Q

5Q=32+8

5Q=40

Q=8

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I’ve looked at this for a while, can someone clear up the answers for me? I can’t figure it out.
navik [9.2K]
What answers? I don't see any
4 0
3 years ago
How to find the derivative of cos^2x? i seem to be confused.
slamgirl [31]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2927231

————————

You can actually use either the product rule or the chain rule for this one. Observe:

•  Method I:

y = cos² x

y = cos x · cos x


Differentiate it by applying the product rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x\cdot cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{dx}(cos\,x)\cdot cos\,x+cos\,x\cdot \dfrac{d}{dx}(cos\,x)}


The derivative of  cos x  is  – sin x. So you have

\mathsf{\dfrac{dy}{dx}=(-sin\,x)\cdot cos\,x+cos\,x\cdot (-sin\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=-sin\,x\cdot cos\,x-cos\,x\cdot sin\,x}


\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark

—————

•  Method II:

You can also treat  y  as a composite function:

\left\{\!
\begin{array}{l}
\mathsf{y=u^2}\\\\
\mathsf{u=cos\,x}
\end{array}
\right.


and then, differentiate  y  by applying the chain rule:

\mathsf{\dfrac{dy}{dx}=\dfrac{dy}{du}\cdot \dfrac{du}{dx}}\\\\\\
\mathsf{\dfrac{dy}{dx}=\dfrac{d}{du}(u^2)\cdot \dfrac{d}{dx}(cos\,x)}


For that first derivative with respect to  u, just use the power rule, then you have

\mathsf{\dfrac{dy}{dx}=2u^{2-1}\cdot \dfrac{d}{dx}(cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2u\cdot (-sin\,x)\qquad\quad (but~~u=cos\,x)}\\\\\\
\mathsf{\dfrac{dy}{dx}=2\,cos\,x\cdot (-sin\,x)}


and then you get the same answer:

\therefore~~\boxed{\begin{array}{c}\mathsf{\dfrac{dy}{dx}=-2\,sin\,x\cdot cos\,x}\end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>derivative chain rule product rule composite function trigonometric trig squared cosine cos differential integral calculus</em>

3 0
4 years ago
How do you solve 8y=48 one step equation
ValentinkaMS [17]
Divide each side by 8

y=6
8 0
4 years ago
Read 2 more answers
The area of the triangle below is 10.6 square centimeters. What is the length of the
CaHeK987 [17]

Answer:

6 cm

Step-by-step explanation:

The area of a triangle is \frac{bh}{2} = A, where b = base, h = height, and A = area. In this case, we're given the height as 4 cm and the area as 6 cm^2.

Let's plug in these values.

  • \frac{4b}{2} = 6

Now, let's solve this algebraically.

Step 1: Multiply both sides by 2.

  • \frac{4b}{2} * 2 = 6 * 2
  • 4b = 12

Step 2: Divide both sides by 4.

  • \frac{4b}{4} = \frac{12}{4}
  • b = 3

Step 3: Check if solution is correct.

  • \frac{3*4}{2} = 6
  • \frac{12}{2} = 6
  • 6 = 6

Therefore, the base is 6 cm. (but don't put the cm in the box because it's already there)

Have a lovely rest of your day/night, and good luck with your assignments! ♡

3 0
3 years ago
Select all the equations on which the point (10,0) lies.
Makovka662 [10]

Answer:

  B, C

Step-by-step explanation:

Since y=0, you are looking for equations such that 10 times the coefficient of x is the constant in the equation.

  a) 5·10 ≠ 15

  b) 2·10 = 20 . . . . select this one

  c) 10 = 10 . . . . select this one

  d) 3·10 ≠ 13

  e) 4·10 ≠ 20

  f) 6·10 ≠ 50

8 0
2 years ago
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