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Strike441 [17]
4 years ago
7

Create your own GCF word problem with 3 numbers

Mathematics
1 answer:
svet-max [94.6K]4 years ago
5 0
Number set:
18, 36, 900
GCF:
9
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Which ratio correctly compares 12 yd to 20 ft, when the lengths are written using the same units?
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Answer:

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Step-by-step explanation:

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3 years ago
Solve using the standard algorithm <br> 1.03 +0.08
nataly862011 [7]

Answer:

1.11

Step-by-step explanation:

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4 0
3 years ago
Jonah is going to the store to buy candles. Small candles cost $2.50 and large candles cost $7.00. He needs to buy at least 20 c
artcher [175]

<em><u>The system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

<em><u>Solution:</u></em>

Let "a" be the number of small candles bought

Let "b" be the number of large candles bought

<em><u>He needs to buy at least 20 candles</u></em>

Therefore, number of small candles and number of large candles bought must be at least 20

Thus, we frame a inequality as:

a + b \geq 20

"at least" means greater than or equal to

Here, we used "greater or equal to" symbol because, he can buy 20 candles or more than 20 candles also

From given,

Cost of 1 small candle = $ 2.50

Cost of 1 large candle = $ 7

<em><u>He can spend no more than 80 dollars</u></em>

Which means, he spend maximum 80 dollars or less than 80 dollars also

So we have to use "less than or equal to" symbol

<em><u>Thus, we frame a inequality as:</u></em>

Number of small candles bought x Cost of 1 small candle + number of large candles bought x Cost of 1 large candle \leq 80

a \times 2.50 + b \times 7 \leq 80\\\\2.50a + 7b\leq 80

<em><u>Thus the system of linear inequalities are:</u></em>

a + b \geq 20\\\\2.50a + 7b\leq 80

3 0
3 years ago
Which expression shows that the quotient
Harrizon [31]

Answer:

Option (2)

Step-by-step explanation:

Given expression is \frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

We further simplify this expression,

\frac{2}{(3x-1)} ÷ \frac{6}{6x-1}

= \frac{2}{(3x-1)}\times \frac{6x-1}{6}

= \frac{6x-1}{3(3x-1)}

= \frac{6x-1}{(9x-3)}

Therefore, \frac{6x-1}{(9x-3)} will be the quotient of the given expression.

x\neq \frac{1}{3} and x\neq \frac{1}{6} for which the given expression is not defined.

Option (2) will be the answer.

6 0
3 years ago
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