Answer:
A.415.69cm
b.323.14
Step-by-step explanation:
The height would be 10cm
The length would be 4cm
Answer:
37.5 feet.
Step-by-step explanation:
1.25/actual height = 1/30
1.25*30 = 37.5 ft
(╹ڡ╹ )
2y^3 – 2y – 10y + 10 + y^2 – 1 < 0 [the terms are simply reorganized again]
factor 2y from the first two terms, -10 from the second two terms
2y (y^2 -1) – 10 (y-1) + y^2 – 1 < 0
2y (y+1)(y–1) – 10 (y-1) + (y+1)(y–1) < 0 [ because y^2 – 1 = (y+1)(y–1) ]
factor out (y-1) from all the terms
(y-1) [2y(y+1)-10+ y+1] < 0
(y-1) [(y+1) (2y+1) - 10] < 0
Let us simplify (y+1) (2y+1) - 10 < 0 now
(y-1) (2y^2+y+2y+1-10) < 0
(y-1) (2y^2 +3y -9 < 0
(y-1) (2y^2 +6y -3y - 9) < 0 [ because 3y = 6y -3y] j
Answer:
7
............................
9514 1404 393
Answer:
72
Step-by-step explanation:
The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:
NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4
This ratio, or scale factor, also applies to the perimeters of the two triangles.
perimeter NPQ / perimeter RSQ = 3/4
Using the given expressions for the perimeters, we have ...
(7x +2)/(10x -4) = 3/4
We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.
4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)
28x +8 = 30x -12 . . . . . eliminate parentheses
20 = 2x . . . . . . . . . . . add 12-28x to both sides
10 = x . . . . . . . . . . . divide both sides by 10
The perimeter of ΔNPQ is ...
7x +2 = 7(10) +2 = 72
The perimeter of triangle NPQ is 72 units.
