Answer: Chuck's travel at a rate of 52mph
Step-by-step explanation:
For Chuck's trip:
D=RT
104= (R+4)T
T= 104 / (R+4)
For Dana's trip:
96 = RT
T= 96/R
Set both equation for Chuck's and Dana together
104/(R+4) =96/R
Then we cross multiply
96(R+4) = 104R
96R + 384 = 104R
104R - 96R = 384
8R = 384
To get R, divide both side by 8
8R/8 = 384/8
R= 48mph
This means Dana's speed is 48mph
Chuck's speed will be: 48mph+4mph = 52mph
Had to look for the options for this question and here is my answer.
Based on the given scenario above regarding Heather school's scheduling, I can say that the question that would be the most appropriate for her to ask is "How do you feel about your child having to take summer school in order to graduate based on this traditional schedule?" Hope this helps.
Https://www.algebra.com/cgi-bin/plot-formula.mpl?expression=highlight%28x%3C=45%29
Answer:
a) P=0.2503
b) P=0.2759
c) P=0.3874
d) P=0.2051
Step-by-step explanation:
We have this information:
25% of American households have only dogs (one or more dogs)
15% of American households have only cats (one or more cats)
10% of American households have dogs and cats (one or more of each)
50% of American households do not have any dogs or cats.
The sample is n=10
a) Probability that exactly 3 have only dogs (p=0.25)
b) Probability that exactly 2 has only cats (p=0.15)
c) Probability that exactly 1 has cats and dogs (p=0.1)
d) Probability that exactly 4 has neither cats or dogs (p=0.5)
