Name the set(s) of numbers to which 1.68 belongs ?

1 answer:

4 0

The answer is First, it is a Rational number. It is also a Real number. If you want one more set, it is a Complex number (if you have had that one yet!).

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Does the table represent an exponential function? Explain why or why not.

Eddi Din [679]

Answer:

No, it does not.

Step-by-step explanation:

It's a linear function, with a slope of -3 (down 3 for every new X as you move right)

7 0

3 years ago

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What is the image of the point (-5, 4) after a rotation of 270° counterclockwise

Illusion [34]

Answer:

(4, 5)

Step-by-step explanation:

this is the same as a 90° rotation clockwise.

with the coordinates of (-5, 4) we start in the top left quadrant (x values are negative, y values are positive).

and we end up in the top right quadrant (x and y values are positive).

the line from the origin to the point is perpendicular (90° angle) to the line of the origin to the original point, as we just rotated by 90° or 270°.

that means the rules for the slope of perpendicular lines apply :

x and y coordinate differences trade places, and the sign of their ratio is flipped.

luckily, because the origin is the reference point for both lines, the point coordinates are automatically the coordinate differences to (0, 0).

and because we need to get 2 positive coordinates, that means

(-5, 4) turns into (4, 5)

as the alternative (-4, -5) would be in the bottom left quadrant.

5 0

3 years ago

Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are

prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

$A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2$

Where:

$\theta = 2\times tan^{-1}( \frac{The \, number \, of \, vertical \, squrare \, sides \ cut \, by \ the \ large \, semicircle}{The \, number \, of \, horizontal \, squrare \, sides \ cut \, by \ the \ large \, semicircle} )$