Answer:
3 cars
Step-by-step explanation:
If 12 cars are needed to carry 36 students,
<em>12</em><em>c</em><em>a</em><em>r</em><em>s</em><em> = 36</em>
the number of cars to carry 9 students will be:
xcars = 9
cross the two equations
36x = 12 X 9
36x = 108
x = 108/36
x= 3
Therefore, 3 cars are needed to carry 9 students
OR
12 cars will carry 36 students
so 1 car will carry, (36/12)students
therefore, 1 car will carry 3 students
So, for 9 students,
9students = 9/3 = 3
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
202 because you can round it to 200
Step-by-step explanation:
To solve, we have to remember PEMDAS (Parenthesis, Exponent, Multiply / Divide, Add or Subtract).
Here, the curly brackets act as parenthesis, so we solve that first.
• 3 + 7 = 10
Then, we multiply by 4.
• 10 • 4 = 40
Finally, we add 6 to 40.
• 40 + 6 = 46.
Our final answer: 46
Answer:
5/48
Step-by-step explanation:
probabilty= 5/12 * 3/12