All categories

3 years ago

Help please I need help

Mathematics

1 answer:

Eddi Din [679]3 years ago

7 0

Answer:

x = 5/13

Step-by-step explanation:

$x+\dfrac{2}{13}=\dfrac{7}{13}\\\\ x+\dfrac{2}{13}-\dfrac{2}{13}=\dfrac{7}{13}-\dfrac{2}{13}\\\\x+0=\dfrac{7-2}{13}\\\\\boxed{x=\dfrac{5}{13}=0.38462}$

You might be interested in

Solve for w<br> 7=-4w+7<br> w=

devlian [24]

Answer:

Step-by-step explanation:

If I'm not mistaken, the answer must be 0.

7-7 is 0, that cancels out

0 divided by -4w is zero. That leaves w alone

w=0. I think that's the answer.

5 0

3 years ago

Which one don’t lie!!!

Travka [436]

Answer:

Step-by-step explanation:

m=y2-y1/x2-x1

4-2=2

6-3=3

2/3

hope this helps =3

7 0

3 years ago

Read 2 more answers

john withdrew $175.75 from his bank account. now he has $450.25 left in his account. what was the original balance in his accoun

Naddika [18.5K]

Answer:

$626

Step-by-step explanation:

450.25+175.75=626

7 0

3 years ago

What is the slope of the graph shown below

stiv31 [10]

Answer:

B=-5

Step-by-step explanation:

Slope=rise/run

The line passes in

P1(-1,3)

and

P2(0,-2)

So slope=(3-(-2))/(-1-0)=5/-1=-5

6 0

3 years ago

What is the equation of a line which includes points (-5, 5) and (2, 5)?

sveta [45]

<h2>Hello!</h2>

The answer is:

The equation of the line which includes the points (-5,5) and (2,5) is:

$y=5$

To find the line which includes the points (-5,5) and (2,5) we can use the following equation:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)$

So, using the points (-5,5) and (2,5), we have:

$y-5=\frac{5-5}{2-(-5)}*(x-(-5))$

$y-5=\frac{0}{2+5}*(x-(-5))$

$y-5=0*(x+5)$

$y-5=0$

$y=5$

We have that the equation of the line which includes the points (-5,5) and (2,5) is:

$y=5$

Have a nice day!

Note: I have attached a picture for better understanding.

8 0

3 years ago