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Hunter-Best [27]
3 years ago
15

Why cant i see answers anymore

Mathematics
2 answers:
Eddi Din [679]3 years ago
7 0

Answer:

reload the page it happens to me but that might mean your gonna have to watch the add again wait nvm it aint working

Step-by-step explanation:

liraira [26]3 years ago
7 0

Answer:

having the same prob rn

Step-by-step explanation:

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A box of 15 cookies costs $9.<br> MY<br> What is the cost for 1 cookie?
Nitella [24]

Answer: $0.6

Step-by-step explanation:

15cookies= $9

1 cookie = x

Cross multiply

15x= 9

Divide both sides by 15

x= 9/15= 3/5= $0.6

4 0
3 years ago
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How does 31÷5 look using Long division
Pavel [41]
I could only figure out the partial quotient way im sorry but i think this could help

3 0
3 years ago
Oscar is 16 yrs old and his sister is 12. what will be the ratio of Oscar's age to his sister's age in 2 years?Write as a fracti
just olya [345]
Oscar's age = 16
Sister's age = 12

Current year: 16 / 12
Simplest form: 4 / 3 ; both are divisible by 4.

2 years after: (16 + 2) / (12 + 2) = 18 / 14 ; add two years to both numbers.

Simplest form: of 18 / 14 is 9 / 7; both are divisible by 2.

4 0
3 years ago
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maya tried to play a new video game.on her first 4 tries,she lost 14 points,lost 8 points,and finnaly gave up.write and find the
Pavel [41]
-22 points is what she lost

4 0
2 years ago
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Sin5A/SinA-cos5A/cosA=4cos2A​
irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

\frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ LHS = \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}   \\  \\  =  \frac{ \sin5A \:\cos A -  \cos5A \:  \sin A}{\sin A \:\cos A }  \\  \\  =  \frac{ \sin(5A -A )}{\sin A \:\cos A}  \\  \\ =  \frac{ \sin 4A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =4\cos 2A \\  \\  = RHS \\  \\ thus \\  \\  \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ hence \: proved

5 0
3 years ago
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