To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that
and the exponent
are divisible by index
. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is: 
Answer:
P(t)=25000+1.12t
Step-by-step explanation:
Now can you help me?
A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:
f(t) = −16t2 + 16t + 32
Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?
Answer:
y = 5/2x - 5
Step-by-step explanation:
You have to rearrange the equation so that it is equal to y.
5x - 2y = 10
(5x - 2y) - 5x = -5x + 10
-2y = -5x + 10
(-2y)/-2 = (-5x)/-2 + (10)/-2
y = 5/2x - 5
T= total length
T=1 2/5 meters + 4 1/5 meters
add the whole #s and the fractions
T= (1+4) + (2/5 + 1/5)
T= 5 3/5 meters total
Hope this helps! :)
Answer Is Option a)4.5 sq.units
Given vertices are X(2,1),Y(5,4) and Z(5,1)
Answer is given above in the image
If you have any doubts see the image or ask in comments box <em>.</em>
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