(x-1)^3 / 2 = 27
For equations like this, we want to isolate x in order to get the value of it.
First, let's multiply both sides by 2 to eliminate the fraction.
(x-1)^3 = 27(2)
Now, let's take the cube root of both sides
(x-1) = ∛(27 * 2)
Now, simplify the root
x - 1 = 3∛2
Add both sides by 1
x = 1 + 3∛2
That's your answer.
Have an awesome day! :)
B (2x+5y=-10) is the answer.
Answer:
1813.137 KJ
Step-by-step explanation:
potential energy of the body = mgH
where m is mass in Kg , g= 9.81 m/sec^2 and H= height in m
here m= 1000 kg, g= 9.81 m/s^2 and H= 607 feet = 607×0.305= 185.135 m
hence the potential energy p= 1000×9.81×185.135= 1813137.2 J
= 1813.137 KJ
hence the potential energy associated with 1 m^3 of water at 607 feet tall taking the mass as 1000 kg is = 1813.137 KJ
Answer:
Step-by-step explanation:
the quadratic function should be as follows:
Now let's confirm that the zeros of the function are 0 and 8
Therefore we can see that if x = 0
the equation is fulfilled
And we also have 
for this expresion to be equal to zero:
thus, if x = 8
the equation is also fulfilled
The zeros of the quadratic function are 0 and 8.
It's both. Look at the gradients between one point then the one after it. It stays constant from one to the next. (Gradient is 2 by the way: (5-3)/(2-1))
