Which of the h-values satisfy the following inequality 6 ( greater than or equal to sign ) h/2?
1 answer:
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Answer:
The probability is 0.02667
Step-by-step explanation:
Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.
So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = P(D2∩D1)/P(D1)
Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:
At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:
P(A)=1/3
P(B)=1/3
P(C)=1/3
Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)
P(D2/D1) = 0.02667
First you had to add by twenty-two from both sides of equation form.
Then simplify by equation.
Next, you divide by four from both sides of equation form.
Finally, simplify by equation.
Final answer:
Hope this helps!
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-Charlie