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sammy [17]
3 years ago
10

the probability of a particular digit is more than 8%. the graph represents the situation. which values are included in the solu

tion set? check all that apply
Mathematics
2 answers:
allsm [11]3 years ago
4 0

Answer:

1 and 4

Step-by-step explanation:

ed 2020

Leto [7]3 years ago
3 0

Answer:

Option B. 1 and Option E. 4

Step-by-step explanation:

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How do you do this question?
quester [9]

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

F(x) = ∫₆ˣ t⁷ dt

F(6) = ∫₆⁶ t⁷ dt

F(6) = 0

3 0
3 years ago
Help I don’t get these at all
uysha [10]

Answer: its D. 24

Step-by-step explanation:

5 0
2 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

                = x*(x² + 2x + 4) - 2*(x² + 2x + 4)

                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

                = x³ + 2x² + 4x  -2x² -4x - 8

                = x³ - 8

2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

7 0
3 years ago
What is the unit price of $4.00 for 26 ounces
MrRissso [65]

Answer:

$.15

Step-by-step explanation:

you take $4.00

divide by the items weight

to get $.1538

round to the nearest full cent

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3 years ago
Electric current flowing through wire produces heat that
morpeh [17]
I’m not sure? But don’t answer the guy with the bitly it’s a scam
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2 years ago
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