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3 years ago

Please help!

2 answers:

5 0

The perimeter in this case will be:

p=2x+y and we are told that p=84yd so

2x+y=84

y=84-2x

Now for the area:

A=xy, and using y found above in this gives you:

A=x(84-2x)

A=84x-2x^2 now taking the derivatives gives you the velocity and acceleration of the area function...

dA/dx=84-4x and d2A/dx2=-4

Since the acceleration is a constant -4, when velocity is equal to zero it is at the absolute maximum value for the area function...

dA/dx=0 only when 84=4x, x=21

So the maximum possible area will occur when x=21

A(21)=84(21)-2(21^2)

A(21)=882 yd^2

musickatia [10]3 years ago

4 0

Answer:

882 yd^2

Step-by-step explanation:

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Solve these and show your work pls!

sertanlavr [38]

Answer :the 1st and 3rd are true

Step-by-step explanation:

you do the math how their set up so just right those and you can get your answer that way. (if your adding a positive and negative your basically subtracting so just write in the order their in; if you subtracting a negative from a positive it equals a positive; if your subtracting a negative from a negative or the answer is positive; if your subtracting a positive from a negative its negative) i hope this helps if u have any more questions just message me and i will be happy to help you anytime!!! <3

3 0

3 years ago

Word problem plz help thanks fam 7.04

givi [52]

g/2 + 4

last option is the answer

4 0

3 years ago

Read 2 more answers

Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Consider the

Dafna1 [17]

Answer:

a) $\bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2$

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311$

b) The 90% confidence interval would be given by (63.330;81.070)

$63.330 < \mu_{left}- \mu_{right}$

Step-by-step explanation:

1) Previous concepts and notation

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Let put some notation

x=left arm , y = right arm

x: 175 169 182 146 144

y: 102 101 94 79 79

The first step is define the difference $d_i=x_i-y_i$ , that is given so we have:

d: 73, 68, 88, 67, 65

The second step is calculate the mean difference

$\bar d= \frac{\sum_{i=1}^n d_i}{n}=72.2$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =9.311$

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar d \pm t_{\alpha/2}\frac{s_d}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,4)".And we see that $t_{\alpha/2}=2.13$

Now we have everything in order to replace into formula (1):

$72.2-2.13\frac{9.311}{\sqrt{5}}=63.330$

$72.2+2.13\frac{9.311}{\sqrt{5}}=81.070$

So on this case the 90% confidence interval would be given by (63.330;81.070)

$63.330 < \mu_{left}- \mu_{right}$

3 0

3 years ago

Tom conducted a drawing competition at school. He bought 5 boxes of colored pencils and spent $5.25 on drawing paper. However, m

tangare [24]

82.92 - 5.25 = 77.67
77.67 divided by 8 =
$9.70 per box

6 0

3 years ago

What is the distance between the points (5,1) and (-3,-5)?<br>

Charra [1.4K]

Answer

$\boxed{10 \: \: units}$

Step by step explanation

Let the points be A and B

A ( 5 , 1 ) ⇒ ( x₁ , y₁ )

B ( -3 , -5 )⇒ ( x₂ , y₂ )

Now, let's find the distance between theses two points:

Distance = $\mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }$

Plug the values

$\mathsf{ \sqrt{ {( - 3 - 5)}^{2} + {( - 5 - 1)}^{2} } }$

Calculate

$\mathsf{ \sqrt{ { ( - 8)}^{2} + {( - 6)}^{2} } }$

Evaluate the power

$\mathsf{ \sqrt{64 + 36} }$

Add the numbers

$\mathsf{ \sqrt{100} }$

Write the number in exponential form with a base of 10

$\mathsf {\sqrt{ {10}^{2} } }$

Reduce the index of the radical and exponent with 2

$\mathsf{10 \: units}$

-------------------------------------------------------------------------------

The distance formula is used to determine the distance ( d ) between two points. If the co-ordinates of the two points are ( x₁ , y₁) and ( x₂ , y₂ ) , the distance equals the square root of x₂ - x₁ squared + y₂ - y₁ squared.

Hope I helped!

Best regards!

6 0

3 years ago