g(θ) = 20θ − 5 tan θ
To find out critical points we take first derivative and set it =0
g(θ) = 20θ − 5 tan θ
g'(θ) = 20 − 5 sec^2(θ)
Now we set derivative =0
20 − 5 sec^2(θ)=0
Subtract 20 from both sides
− 5 sec^2(θ)=0 -20
Divide both sides by 5
sec^2(θ)= 4
Take square root on both sides
sec(θ)= -2 and sec(θ)= +2
sec can be written as 1/cos
so sec(θ)= -2 can be written as cos(θ)= -1/2
Using unit circle the value of θ is 
sec(θ)= 2 can be written as cos(θ)=1/2
Using unit circle the value of θ is 
For general solution we add 2npi
So critical points are

Answer:
24.8
Step-by-step explanation:
sin75 = 24/x
x = 24/sin75 = 24.8466 = 24.8 (nearest tenth)
400. Just add a zero when you're dealing with tens
Answer:
0.683
Step-by-step explanation:
We have to find P(-1<z<1).
For this purpose, we use normal distribution area table
P(-1<z<1)=P(-1<z<0)+(0<z<1)
Using normal area table and looking the value corresponds to 1.0, we get
P(-1<z<1)=0.3413+0.3413
P(-1<z<1)=0.6826
Rounding the answer to three decimal places
P(-1<z<1)=0.683
So, 68.3% of the z-scores will be between -1 an 1.