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Lady_Fox [76]
2 years ago
7

Please help!

Mathematics
2 answers:
kondaur [170]2 years ago
5 0
The perimeter in this case will be:

p=2x+y  and we are told that p=84yd so

2x+y=84

y=84-2x

Now for the area:

A=xy, and using y found above in this gives you:

A=x(84-2x)

A=84x-2x^2  now taking the derivatives gives you the velocity and acceleration of the area function...

dA/dx=84-4x and d2A/dx2=-4

Since the acceleration is a constant -4, when velocity is equal to zero it is at the absolute maximum value for the area function...

dA/dx=0 only when 84=4x, x=21

So the maximum possible area will occur when x=21

A(21)=84(21)-2(21^2)

A(21)=882 yd^2  
musickatia [10]2 years ago
4 0

Answer:

882 yd^2

Step-by-step explanation:


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Answer:

Step-by-step explanation:

\begin{vmatrix}3 & -1\\ -3 & 4\end{vmatrix}=(3\times 4)-(-1)\times (-3)

               = 12 - 3

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\begin{vmatrix}8 & -1\\ -4 & -1\end{vmatrix}=8\times(-1)-(-1)\times(-4)

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\begin{vmatrix}-12 & -1\\ 12 & 5\end{vmatrix}=(-12)\times(5)-(-1)\times(12)

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\begin{vmatrix}2 & -1\\ 2 & -1\end{vmatrix}=2\times(-1)-(2)\times(-1)

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            = 0

\begin{vmatrix}0 & -1\\ 17 & 4\end{vmatrix}=0\times(4)-(-1)\times(17)

              = 17

\begin{vmatrix}1 & 0\\ 0 & 1\end{vmatrix}=1\times(1)-(0)\times(0)

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6 0
2 years ago
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Explanation:

Angle TSU is formed when we bisect angle RSU. Recall that bisect means to cut in half. So TSU is half of RSU. Put another way, RSU is twice that of TSU.

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Hope this helps!

:)

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