If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
<h3>Discriminant: </h3>
The quadratic formula includes the discriminant, which comes after the square root. The discriminant of a quadratic equation is important because it indicates the quantity and kind of solutions.
The formula for the Discriminant of a Quadratic Equation ax²+bx +c = 0 is given by
<h3> Discriminant Δ = b² - 4ac </h3>
Here we have
x² + 16x + c = 0 equation has only one real solution
Compare given equation with ax²+ bx + c = 0
=> a = 1, and b = 16
As we know when an equation has only one real solution
then its Discriminant will be equal to zero
=> b² - 4ac = 0
By the above values,
=> 16² - 4(1)c = 0
=> 256 - 4c = 0
=> 4c = 256
=> c = 256/4
=> c = 64
Therefore,
If the equation x² + 16x + c = 0 has only one real solution, the value of c is equal to 64.
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Answer:
B
Step-by-step explanation:
√256=16
√289=17
Answer:
well the ratio is 1 : 4 so x is 16
Step-by-step explanation:
Answer:
2x - 13
Step-by-step explanation:
Step 1 :
1
Simplify —
2
Equation at the end of step 1 :
1
(-4x - 2) + (— • (12x - 22))
2
Step 2 :
Pulling out like terms :
3.1 Pull out like factors :
12x - 22 = 2 • (6x - 11)
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
12x - 22 = 2 • (6x - 11)
Equation at the end of step 3 :
(-4x - 2) + (6x - 11)