Answer:
The complete function is as follows:
def get_nth_int_from_CSV(CSV_string, index):
splitstring = CSV_string.split(",")
print(int(splitstring[index]))
Explanation:
This defines the function
def get_nth_int_from_CSV(CSV_string, index):
This splits the string by comma (,)
splitstring = CSV_string.split(",")
This gets the string at the index position, converts it to an integer and print the converted integer
print(int(splitstring[index]))
<u>Answer</u>:
<em>A player centric game would be one of the best game where the player would navigate till the end of the game. </em>
<u>Explanation</u>:
It is the game, where the designer considered himself as <em>a player and make the background picture, music, character, challenge </em>everything would be tackled in a fun-filled way.
A <em>designer centric game would be a one, where the player wouldn’t enjoy playing and will never be able to complete the entire game</em> and would have been tired of listening to the background music and other <em>unfriendly aspects in the game.</em>
Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
<span>D - graphical user interface</span>
