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MatroZZZ [7]
3 years ago
12

X=square root of 880-8x

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0
x=\sqrt{880-8x}\\
D:880-8x\geq0 \wedge x\geq0\\
D:8x\leq880 \wedge x\geq0\\
D:x\leq 110 \wedge x\geq0\\
D:x\in\langle0,110\rangle\\
x^2=880-8x\\
x^2+8x-880=0\\
x^2+8x+16-896=0\\
(x+4)^2=896\\
x+4=8\sqrt{14} \vee x+4=-8\sqrt{14}\\
x=-4+8\sqrt{14} \vee x=-4-8\sqrt{14}\\
\\ x=-4-8\sqrt{14}\not \in D \Rightarrow \boxed{x=-4+8\sqrt{14}}
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m=(y2-y1)/(x2-x1)

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in this equation the slope is 2, and to find the first equation, use y=mx+b

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the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2

for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b

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Step-by-step explanation:

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