Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:
Aqueous ferric sulfate = 
Gaseous sulfur dioxide = 
Water = 
Aqueous sulfuric acid = 
Aqueous ferrous sulfate = 
Thus, the balance equation becomes:
+
+

More on ferrous sulfate can be found here: brainly.com/question/10834028
Answer: limiting reactant controls the amount of product formed in a chemical reaction.
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Answer:
Figure 1 provides the rawest and most accurate data.
Explanation:
Answer:
C₅H₁₀O₅
Explanation:
1. Calculate the mass of each element in 2.78 mg of X.
(a) Mass of C

(b) Mass of H

(c) Mass of O
Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g
2. Calculate the moles of each element

3. Calculate the molar ratios
Divide all moles by the smallest number of moles.

4. Round the ratios to the nearest integer
C:H:O = 1:2:1
5. Write the empirical formula
The empirical formula is CH₂O.
6. Calculate the molecular formula.
EF Mass = (12.01 + 2.016 + 16.00) u = 30.03 u
The molecular formula is an integral multiple of the empirical formula.
MF = (EF)ₙ

MF = (CH₂O)₅ = C₅H₁₀O₅
The molecular formula of X is C₅H₁₀O₅.