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34kurt
3 years ago
12

Ann swims the length of a 50 meter swimming pool in 25 seconds. what is her average speed.

Chemistry
1 answer:
zalisa [80]3 years ago
7 0

Answer:

2m/s

Explanation:

2meters/second

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A helium filled weather balloon has a volume of 806 L at 20.9°C and 753 mmHg. it is released and rises to an altitude of 6.8 km,
OLEGan [10]
<h3>Answer:</h3>

1257.45 L

<h3>Explanation:</h3>

We are given;

  • Initial volume of Helium gas, V1 as 806 L
  • Initial temperature of Helium gas,T1 as 20.9°C
  • Initial pressure of Helium gas, P1 as 753 mmHg
  • Pressure of Helium at the altitude 6.8 km, P2 as 417 mmHg
  • Temperature of Helium gas at the altitude 6.8 Km, T2 as -19.1°C

But, K = °C + 273.15

Therefore, T1 = 294.05 K and T2 = 254.05 K

  • We are required to calculate the new volume of the balloon at 6.8 km.
  • To determine the new volume we are going to use the combined gas law.
  • According to the combined gas law, \frac{P1V1}{T1}=\frac{P2V2}{T2}

Thus, rearranging the formula;

V2=\frac{P1V1T2}{P2T1}

V2=\frac{(753)(806L)(254.05K)}{(417)(294.05)}

V2=1257.45L

Therefore, the volume of the balloon at an altitude of 6.8 km is 1257.45 L

7 0
3 years ago
1144 grams of Chromium =<br> number.<br> moles of Chromium, rounded to the nearest whole
likoan [24]

Answer:

22moles

Explanation:

3 0
3 years ago
"Thermite" reactions have been used for welding metal parts such as railway rails and in metal refining. One such thermite react
frosja888 [35]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

3Mg(s)+Cr_2O_3(s)\rightarrow 3MgO(s)+2Cr(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(3\times \Delta S^o_{(MgO(s))})+(2\times \Delta S^o_{(Cr(s))})]-[(3\times \Delta S^o_{(Mg(s))})+(1\times \Delta S^o_{(Cr_2O_3(s))})]

We are given:

\Delta S^o_{(Mg(s))}=32.68J/K.mol\\\Delta S^o_{(Cr_2O_3(s))}=81.2J/K.mol\\\Delta S^o_{(MgO(s))}=26.94J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(3\times (26.94))+(2\times (23.77))]-[(3\times (32.68))+(1\times (81.2))]\\\\\Delta S^o_{rxn}=-50.88J/K=-0.0509kJ/K.mol

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

To calculate the standard Gibbs free energy of the reaction, we use the equation:

\Delta G^o=\Delta H^o-T\Delta S^o

where,

\Delta G^o = standard Gibbs free energy = ?

\Delta H^o = standard enthalpy change of the reaction = 665.1 kJ/mol

T = Temperature = 298.15 K

\Delta S^o = standard entropy change of the reaction = -0.0509 kJ/K.mol

Putting values in above equation, we get:

\Delta G^o=(665.1kJ/mol)-(298.15K\times (-0.0509kJ/K.mol))=680.27kJ/mol

As, the Gibbs free energy of the reaction is coming out to be positive, the reaction is non-spontaneous in nature.

Hence, the given reaction is non-spontaneous in nature.

4 0
4 years ago
A sample contains 6.73 g of Na2CO3 in water to make a total of 250.0 mL of solution. What is the molarity of sodium carbonate in
wlad13 [49]

Answer:

Molarity of Na₂CO₃ = 0.25M

% mass = 2.69

Explanation:

Molarity means mole of solute in 1L of solution

Molar mass of solute (Na₂CO₃) = 105,98 g/m

Moles = mass / molar mass → 6.73 g / 105.98 g/m = 0.0635 m

Mol/L = [M]

0.0635 mol/0.250L = 0.25M

Density of solution = Solution mass / Solution volume

1 g/ml = Solution mass / 250 mL → Solution mass is 250g

% mass will be:

In 250 g of solution we have 6.73 g of solute

in 100 g of solution we have (100 . 6.73)/250 = 2.69

6 0
3 years ago
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What energy do glow sticks convert to ?
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Is there any multiple choices?
8 0
3 years ago
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