Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
The answer is A) -9.272
Step-by-step explanation:
-5.872 + (-5.1)/1.5
= -5.872 - 3.4
= -9.272
To find the circumference of a round object, you will take the diameter and multiply is by pi to get 78.5mm
I think the answer would be 99
you multiply 9 and 11 and get 99
The rachos were sold are 6
because ratio of them at the begining = 3/4
after selling some popcorns, ratio of them still 3/4
they sold 8 popcorns mean 3/4 = ?rachos / 8popcorns sold
the rachos sold = 3*8/4 = 6
