Ask question

Ask question

All categories

2 years ago

14

Which one is a quadratic function

1 answer:

erastova [34]2 years ago

5 0

Answer:

Step-by-step explanation: A or the top answer choice. The highes exponent needs to be 2.

You might be interested in

Which statement is always true? A.) The absolute value of an integer is equal to the opposite of the integer B.) a positive inte

Ahat [919]

Answer:

the absolute value of an integer is equation to the opposite of the integer

3 0

3 years ago

Read 2 more answers

HELP PLEASE!! Fast ;))

Tom [10]

What is the volume of the composite figure? (Use for .) Do NOT round your answer

answer- 2388.16

in- 3

3 0

1 year ago

Read 2 more answers

A children's inflatable pool takes 22 minutes to fill with an electric air pump. It takes 50 minutes to let the air out of the p

WARRIOR [948]

Im assuming it has the same amount of air pressure so it wold take roughly double the time. So I would say 44 minutes.

6 0

3 years ago

When solving the equation -2x = 14 . how would you solve for x?

77julia77 [94]

Answer:

Dividing -2 on both sides

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

1 year ago