Ask question

Ask question

All categories

Varvara68 [4.7K]

2 years ago

5

Mrs. chill has 26 yards of ribbon. She places equal amounts on 3 different spools to sell. How much ribbon in yards are on each

spool

1 answer:

den301095 [7]2 years ago

6 0

8.6 yards are on each spool

You might be interested in

This week Kent worked 15 hours at $12.50 an hour. His paycheck, including his commission, was $263.85. Ken wants to

EastWind [94]

Answer:

A

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Which of the following values in the set below will make the equation 2x + 1 = 3 true? (Only input the number.)

slava [35]

The only one that makes sense is 1

7 0

2 years ago

Read 2 more answers

Box plots! pls help!

aliina [53]

Answer:

the answer is b i thinkk.

8 0

2 years ago

Read 2 more answers

The relationship between the amount of data downloaded d, in megabytes, and the time t, in seconds, after the download started i

svetoff [14.1K]

Answer: A, C, F, there’s 4 but I only know 3

6 0

2 years ago

Read 2 more answers

Plllzzz im new and i neeed help

ella [17]

Answer:

4082

Step-by-step explanation:

Given

The composite object

Required

The volume

The object is a mix of a cone and a hemisphere

Such that:

<u>Cone</u>

$r = 10cm$ ---- radius (r = 20/2)

$h = 19cm$

<u>Hemisphere</u>

$r=10cm$

The volume of the cone is:

$V_1 = \frac{1}{3}\pi r^2h$

$V_1 = \frac{1}{3}\pi * 10^2 * 19$

$V_1 = \frac{1900}{3}\pi$

The volume of the hemisphere is:

$V_2 = \frac{2}{3}\pi r^3$

$V_2 = \frac{2}{3}\pi 10^3$

$V_2 = \frac{2000}{3}\pi$

So, the volume of the object is:

$V = V_1 + V_2$

$V = \frac{1900}{3}\pi + \frac{2000}{3}\pi$

$V = \frac{3900}{3}\pi$

$V = 1300\pi$

$V = 1300 * 3.14$

$V = 4082$

8 0

2 years ago