Answer:
the student in question bought 3 large notebooks and 3 small notebooks
Step-by-step explanation:
the easiest way to explain how to do this is by recognizing that the student bought $54 worth of notebooks- which is not divisible by 10 easily. that means, we should subtract 8 from 54 until we get a number that IS divisible
54 - 8 = 46 (one small notebook)
46 - 8 = 38 (two small notebooks)
3 8 - 8 = 30 (three small notebooks)
then, divide 30 by 10 to see how many large notebook the student bought.
30/10 = 3
the student in question bought 3 large notebooks and 3 small notebooks
Answer:
95% confidence interval for the proportion of internet users who say online groups have helped solved a problem is between a lower limit of (0.65 - 0.9349/√n) and an upper limit of (0.65 + 0.9349/√n).
Step-by-step explanation:
Confidence interval for a proportion is given as p +/- margin of error (E)
p is the proportion of internet users who say online groups have helped solved a problem = 65% = 0.65
Let the number of internet users be represented by n
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value corresponding to infinity degrees of freedom and 5% significance level is 1.96
E = critical value × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.65(1-0.65) ÷ n] = 1.96 × sqrt(0.2275 ÷ n) = 1.96×0.477/√n = 0.9349/√n
Lower limit of proportion = p - E = 0.65 - 0.9349/√n
Upper limit of proportion = p + E = 0.65 + 0.9349/√n
95% confidence interval is (0.65-0.9349/√n, 0.65+0.9349/√n)
17,900 * (1 -0.13)^7 = 6752.86 . . . . dollars
Answer:
(6, -4)
Step-by-step explanation:
If ABCD is dilated by a factor of 2, you multiply the coordinates by 2. For the coordinate D', you would multiply 3 by 2 to get 6 and you would multiply -2 by 2 to get -4. Answer: (6, -4)
