Answer:
185 minutes.
Step-by-step explanation:
It is possible to model an equation for this, such that

where x represents the number of minutes.
Then, you solve for x:

I’m not the best at math, but ⬇️
For example, apply the distributive property to the expression 3(2 + x) to produce the equivalent expression 6 + 3x; apply the distributive property to the expression 24x + 18y to produce the equivalent expression 6 (4x + 3y); apply properties of operations to y + y + y to produce the equivalent expression 3y
Answer:
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
Step-by-step explanation:


![\sqrt[nt]{\frac{a}{p}} =(1+\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20%20%3D%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29)
![\sqrt[nt]{\frac{a}{p}} -1 =(\frac{r}{n} )](https://tex.z-dn.net/?f=%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%3D%28%5Cfrac%7Br%7D%7Bn%7D%20%29)
![n = \frac{r}{\sqrt[nt]{\frac{a}{p}} -1 }](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Br%7D%7B%5Csqrt%5Bnt%5D%7B%5Cfrac%7Ba%7D%7Bp%7D%7D%20-1%20%7D)
[ Do not confuse, as there are 2 n's, one in subject and another as power. We can never make the power or in a root, the subject. In order to solve for n, we have to make the character "n", the subject. ]
<u><em>⬇ Hey, the answer is down below! :) ⬇</em></u>
<u><em>For y:</em></u> x = -3
For y it stays the same.
<u><em>For x:</em></u> y = 2
For x it stays the same too.
<u><em>For 1.):</em></u> 
Step-by-step explanation:
<u><em>For y there is no step-by-step explanation unfortunately.</em></u>
<u><em>For x there isn't a step-by-step explanation too unfortunately.</em></u>
<u><em>⬇ For 1.) there is a step-by-step explanation! ⬇</em></u>
For step 1 we should flip the equations.
6x + 8 = y
For step 2 we should add -8 to both sides.
6x + 8 + − 8 = y + −8
= 6x = y − 8
For step 3 we should divide both sides by 6.

= x = 
<u><em>In result we should have</em></u>
<u><em>as the answer!</em></u>