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3 years ago

What is 10 less than X

Mathematics

2 answers:

Arada [10]3 years ago

5 0

$x-10$
...........

mina [271]3 years ago

4 0

The answer is X-10 if that was what you wanted to know

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I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

3 years ago

Cassie Boland earns $16.25 an hour. What gross wages did she

sergejj [24]

Answer:

$406.25

Step-by-step explanation:

Multiply 16.25 by 25:

16.25(25)

= 406.25

So, her gross wages were $406.25

6 0

4 years ago

Read 2 more answers

Find the value of a. Round to the nearest tenth, if necessary. 11 24 a

Masja [62]

Answer:

21.3

Step-by-step explanation:

It's easier to see how to do this if you transfer the 11 to the bottom of the rectangle. The look at the left triangle. It has 3 sides.

24, 11, and a.

You should be able to find a using

a^2 + 11^2 = 24^2 Expand the squares

a^2 + 121 = 576 Subtract 121 from both sides

a^2 = 576 - 121

a^2 = 455 Take the square root of both sides.

sqrt(a^2) = sqrt(455)

a = 21.33

a = 21.3

3 0

3 years ago

A triangle has side lengths measuring 2x + 2 ft x + 3 ft, and

Marta_Voda [28]

Answer:

$3x+5 < n < x-1$

Step-by-step explanation:

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the Triangle Inequality Theorem

1) $(2x+2)+(x+3) > n$

solve for n

$3x+5> n$

Rewrite

$n$

2) $(x+3)+n> 2x+2$

$n> x-1$

therefore

$3x+5 < n < x-1$

5 0

3 years ago

Solve the iniquality 6x - 8 > 4x + 26

lesya692 [45]

Answer:

x > 17

Step-by-step explanation:

Add 8 to both sides:

6x - 8 > 4x + 26

6x > 4x + 34

Subtract 4x from both sides:

2x > 34

Divide each side by 2:

x > 17

So, the solution is x > 17

7 0

3 years ago

Read 2 more answers