Sandra and Monica are both saving money. The equation y = 82x

According to a recent study of 7335 young people in the US, 30% had been arrested for a crime other than a traffic violation by

victus00 [196]

Answer:

a) Statistic.

b) The population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

Step-by-step explanation:

a) The proportion of 30% is a statistic, as it is a value that summarizes data only from the sample taken in the study from USA Today. Other samples may yield different proportions.

b) We can use the statistic to estimate a confidence interval for the parameter of the population.

The standard error for the proportion is calculated as:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{N}}=\sqrt{\dfrac{0.3\cdot 0.7}{7335}}=\sqrt{2.83\cdot10^5}= 0.00535$

The margin of error is 0.01. We can use this value to determine the level of confidence that represents.

The formula for the margin of error is:

$E=z\cdot \sigma_p=0.01\\\\z\cdot 0.0535=0.01\\\\z=1.87$

This z-value, according to the the standard normal distribution, corresponds to a confidence interval of 94%.

The interval for this margin of error is:

$p-E\leq \pi \leq p+E\\\\0.30-0.01\leq \pi \leq 0.30+0.01\\\\0.29\leq \pi \leq 0.31$

Then, we can conclude that the population proportion is expected to be between 0.29 and 0.31 with a 94% degree of confidence.

3 0

3 years ago

If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

(c)5 days

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

7 0

2 years ago

Read 2 more answers

In a pack of candies, Maria found that for every three blue candies, there were five red ones. Identify the correct list of rati

Yanka [14]

Answer:

5/3; 5 to 3; 5:3

Step-by-step explanation:

7 0

3 years ago

Expand & simplify:<br>3 (C-7)+2(3c+4)

cupoosta [38]

Answer: 3 (C-7)+2(3c+4)

Step-by-step explanation: Given

3(c - 7) + 2(3c + 4) ← distribute both parenthesis

= 3c - 21 + 6c + 8 ← collect like terms

= 9c - 13

4 0

3 years ago

Javier has 4 juice boxes and 3 are grape flavored write two fractions that describe the juice boxes that is grape

Sunny_sXe [5.5K]

Answer:

G = 3/4 x=1/4

Step-by-step explanation:

so if he has four boxes of juices and three of the are grape that means he has one box that is another

grape = 3/4

another 1/4

3 0

3 years ago