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2 years ago

Paul has AP Calculus test scores of 88, 75, 95, 81, and 93. Find the average of the test scores.

Mathematics

1 answer:

KengaRu [80]2 years ago

6 0

Answer: 86.4

Step-by-step explanation:

To find the average of any numbers you have to find the mean which is basically adding all of the numbers up and then dividing that answer by the number of numbers you have. In this case its:

88 + 75 + 95 + 81 + 93 = 432

432 is now going to be divided by 5, which is the total amount.

432/5 = 86.4 is the average #.

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Determine the slope (9,2) and (3,-8)

Oxana [17]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 2~) 
% (c,d)
&&(~ 3 &,& -8~)
\end{array}
\\\\\\
% slope = m
slope = m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-2}{3-9}\implies \cfrac{-10}{-6}\implies \cfrac{5}{3}$

7 0

3 years ago

PLEASE HELPPPPPPPPPP

Sauron [17]

Answer:

167/346 or 0.483

Step-by-step explanation:

From the question given above, the following data were obtained:

Number of Tails (T) = 167

Number of Heads (H) = 179

Probability of tail, P(T) =?

Next, we shall determine total outcome. This can be obtained as follow:

Number of Tails (T) = 167

Number of Heads (H) = 179

Total outcome (S) =?

S = T + H

S = 167 + 179

Total outcome (S) = 346

Finally, we shall determine the probability of tails. This can be obtained as follow:

Number of Tails (T) = 167

Total outcome (S) = 346

Probability of tail, P(T) =?

P(T) = T / S

P(T) = 167 / 346

P(T) = 0.483

Thus, the probability of tails is 167/346 or 0.483

3 0

2 years ago

PLEASE SOMEONE HELP ILL GIVE BRAINLIEST!

grin007 [14]

Answer:

Part A

The rotation of the point (x, y) 180° about the origin gives the point (-x, -y)

Therefore, we have the points, ΔLMN, L(1, 1), and M(2, 2), and N(3, 3)

The coordinates of the vertices of the image, ΔL'M'N' are L'(-1, -1), and M'(-2, -2), and N'(-3, -3)

Please find attached the graph of triangle ΔLMN and ΔL'M'N'

Part B

The lines drawn through L and L' and through M and M' are colinear

Part C

A line is defined by two points, such as <em>L </em>and <em>M.</em> Rotation of a line through 180° about the origin will give an image location on the same path as the extension of the original line.

The third point, <em>N</em>, however, defines a plane, and the rotation of a plane by 180° will give an image which is turned upside down with regards to the preimage

Therefore, a trough in the preimage becomes a peak in the image and the lines drawn through N and N' crosses the colinear lines drawn throgh M and M' and L and L'

Step-by-step explanation: