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scoundrel [369]
3 years ago
8

7/8 of 16 = what with work

Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0
In order to solve this kind of problem, you have to multiply 7/8 with 16, 

\frac{7}{8} * \frac{16}{1}=  \frac{112}{8}=14

so 14 is the solution
trapecia [35]3 years ago
3 0
7/8times16/1 gives 112/8, which is 14.
you multiply both numerators over both denominators.
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Pie r squared is the area of a circle, so 9^2(3.14etc) = so 255 square yards. So 255 x 15 = $3,825
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3 years ago
Square root of 6 minus square root of 7 divided by square root of 6 plus square root of 7
zheka24 [161]
\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \\ 
 Multiply \ and \ divide \ by \ the \ conjugate. \\ 
 =\frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}+ \sqrt{7} } \times \ \frac{ \sqrt{6}- \sqrt{7} }{ \sqrt{6}- \sqrt{7} } \\ 
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\frac{( \sqrt{6}- \sqrt{7})^2 }{ \sqrt{6}^2 - \sqrt{7}^2 }} \\ 
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 = -( \sqrt{6}^2-2( \sqrt{6} \sqrt{7}+ \sqrt{7}^2 \\ 
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6 0
3 years ago
Consider the functions f(x) = 2x + 1 and g(x) = x^2 - 10. What is the value of f[g(3)]?
ziro4ka [17]

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7 0
3 years ago
Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.3 cus
likoan [24]

Given Information:

Average customer arrival = λ =2.3 customers/hour

Average consultant time1 = μ  = 8 minutes/customer

Average consultant time2 = μ  = 10 minutes/customer

Cost of consultants service = $16

Cost of customer waiting time = $25

Required  Information:

Use one consultant with an average service time of 8 minutes/customer or use two consultants, each with average service time of 10 minutes/customer ?

Answer:

it is recommended to use one consultant with an average service time of 8 minutes/customer.

Step-by-step explanation:

Convert the average consultant time to hours/customer

Average consultant time1 = μ  = 60/8 = 7.5 hours/customer

Average consultant time2 = μ  = 60/10 = 6 hours/customer

Single consultant queuing model:

Calculations for one consultant

Average no. of customers waiting for service = Lq = λ²/μ(μ-λ)

Average no. of customers waiting for service = Lq = (2.3)²/7.5(7.5 - 2.5)

Average no. of customers waiting for service = Lq = 0.1356

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1356 + 2.3/7.5

Average no. of customers in the system = L = 0.442

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.442 + $16

Total cost = $27.05

Multi consultant queuing model:

Calculations for two consultants

Average no. of customers waiting for service = Lq = ((λ/μ)^k(λμ)/(k -1)(kμ - λ))*P₀

Where k = 2 is the number of consultants and P₀ is the probability that all of the k consultants are idle. The value of P₀  can be found in the tables with λ/μ = 2.3/6 = 0.38 and k = 2,  P₀ ≅ 0.685

Average no. of customers waiting for service = Lq = (2.3/6)²(2.3*6)/(2-1)(2*6 - 2.3)*0.685

Average no. of customers waiting for service = Lq = 0.1431

Average no. of customers in the system = L = Lq + λ/μ

Average no. of customers in the system = L = 0.1431 + 2.3/6

Average no. of customers in the system = L = 0.5264

Total cost = (customer waiting time cost)*L + consultant service cost

Total cost = $25*0.5264 + ($16)*2 (since there are 2 consultants now)

Total cost = $45.16

Conclusion:

Therefore, it is recommended to use one consultant with an average service time of 8 minutes per customer since the total cost is less than the other option.

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