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charle [14.2K]
3 years ago
7

Which of the following best describes the ordered pairs listed below?

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

Answer:

D. Relation only.

Step-by-step explanation:

This is a one-to-many relation ( because -2 maps on to -4 and -11)  so it is a relation but NOT a function. A function is a one-one or many-to-one relation.

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Choose the correct symbol from the drop-down list to compare the rational number
Kay [80]

Answer:

>

Step-by-step explanation:

If we plot -1.5 and -1.76, we would see thant -1.5 is to the right of -1.76

Right means larger here, so -1.5 is larger

3 0
2 years ago
Read 2 more answers
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
1 year ago
How do I solve this?
Ivenika [448]

\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}


\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2

7 0
3 years ago
What happens to the food supply when food prices are high?
IgorC [24]
<span>B. The food supply diminishes in all socioeconmic classes. 
</span>
3 0
3 years ago
Will side lengths of 3 cm, 4 cm, and 5 cm form a triangle? explain.
Gelneren [198K]

Yes, that is the famous first Pythagorean triplet: 3²+4²=5²

or

For three lengths to be able to form a triangle, it suffices that every one of those lengths is shorter than the sum and longer than the difference of the other two.

It is enough to check just one side.

So,

3 + 4 > 5

4 - 3 < 5

Your triangle is constructible.

6 0
3 years ago
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