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Vera_Pavlovna [14]
3 years ago
11

Quadrilateral ABCD is similar to quadrilateral EFGD. Which angle of quadrilateral ABCD corresponds to

Mathematics
1 answer:
topjm [15]3 years ago
7 0
<D is corresponding to <CGF

answer is <D last choice
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Margo’s dog, named Todd, weighed 120 pounds last year. She now weighs 180 pounds. What is the percent of change
elixir [45]

Answer:

50%

Step-by-step explanation:

the increase is 60 so divide that by the original number; 60/120=0.5

now we have to change the decimal to a percent. multiply by 100 to do that and we get 50%.

3 0
3 years ago
Read 2 more answers
Please do all problems with work on paper thank you​
damaskus [11]

a. \frac{11}{12}

b. \frac{39}{20}

c. \frac{20}{21}

Step-by-step explanation:

Step 1; First, we convert the given fractions into improper ones. To do this, we multiply the whole number with the denominator of the fraction and add with it the same fraction's numerator whereas the denominator remains unchanged. To convert the fraction

3\frac{1}{4} = (3 × 4) + 1 / 4 = \frac{13}{4},

2\frac{1}{3} = (2 × 3) + 1 / 3 = \frac{7}{3},

6\frac{1}{5} = (6 × 5) + 1 / 5 = \frac{31}{5},

4\frac{1}{4} = (4 × 4) + 1 / 4 = \frac{17}{4},

5\frac{2}{7} = (5 × 7) + 2 / 7 = \frac{37}{7},

4\frac{1}{3} = (4 × 3) + 1 / 3 = \frac{13}{3}.

Step 2; Now we subtract, using LCM to arrive at the answer

3\frac{1}{4} - 2\frac{1}{3} = \frac{13}{4} - \frac{7}{3} = \frac{39-28}{12} = \frac{11}{12},

6\frac{1}{5} - 4\frac{1}{4} = \frac{31}{5} - \frac{17}{4} = \frac{124-85}{20} = \frac{39}{20},

5\frac{2}{7} - 4\frac{1}{3} = \frac{37}{7} - \frac{13}{3} = \frac{111-91}{21} = \frac{20}{21}.

7 0
3 years ago
925÷25 show working i know the answer is 37 how did you get 37​
Lina20 [59]

Answer:

37

Step-by-step explanation:

4 0
3 years ago
Which of the following equations have complex roots?
goldenfox [79]

9514 1404 393

Answer:

  B.  3x² +2 = 0

Step-by-step explanation:

The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)

__

The equation of B can be rewritten as ...

  x² = -2/3

This will have complex roots.

__

The discriminants of both equations C and D are positive, so those have only real roots.

  2x² -5x -1   ⇒   d = (-5)² -4(2)(-1) = 33

  3x² -6x -1   ⇒   d = (-6)² -4(3)(-1) = 48

6 0
3 years ago
What does x equal? <br> :))
Daniel [21]

If you multiply out the first side of the equation, (x + 5)³, it's equal to the second side.

x³ + 5³ = x³ + 5³, so any value of x would work.

x = "any real number" would be your answer, unless you can't type. then I think anything would work (I'm not certain though!) :)

8 0
3 years ago
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