The <u>probability</u> that a point <u>chosen at random</u> in the triangle is also in the blue square can be calculated using <u>geometrical definition of the probability</u>:
1. Find the total area of the triangle:
2. Find the desired area of the square:
Then the probability is
Answer: correct choice is B
Answer:
n = 2/9
Step-by-step explanation:
switch sides: 63n=14
divide both sides by 63: 63n/63 = 14/63
simplify: n = 2 / 9
Hello from MrBillDoesMath!
Answer: N = 143
Discussion:
This one took some trial and error! At first I listed all 2 digit primes, looked at the list, but didn't know how to proceed. So, I took the smallest 2 digit primes numbers: 11 and 13 and wondered if their product, 13*11 = 143, could be represented as the sum of 3 consecutive primes. I went back to my list of primes, added groups of three consecutive numbers that seemed to be in the right range to give the desired sum, and stumbled on 43, 47, and 53!
43 + 47 + 53 = 143 !
Therefore N = 143. It's the sum of 43, 47, and 53 as well as the product of 11 and 13.
Thank you,
MrB
Answer:
B
Step-by-step explanation:
since K is constant ( the same for every point) we can find k when given any point by dividing the y-coordinate by the x-coordinate.
Answer:
B or the third option you put.
Step-by-step explanation:
