Lyra's speed of travel is 6.71 feet per seconds and Lyra's direction of travel is 27 degrees north of east
<h3>How to determine the speed of travel?</h3>
The diagram that represents the scenario is added as an attachment.
Let x represents Lyra's speed of travel.
The value of x is calculated using the following Pythagoras theorem.

Evaluate the exponents

Evaluate the sum

Evaluate the exponent
x = 6.71
Hence, Lyra's speed of travel is 6.71 feet per seconds
<h3>How to determine the direction of travel?</h3>
The direction (∅) is calculated using the following tangent ratio.

Evaluate the quotient

Take the arc tan of both sides

Evaluate

Hence, Lyra's direction of travel is 27 degrees north of east
Read more about speed and distance at:
brainly.com/question/4931057
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