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Kryger [21]
4 years ago
5

A 1600 Watts electric oven is used for 9 hours. Calculate the cost of using the $3.00 per unit of energy (Energy consumed = powe

r× time)​
Mathematics
1 answer:
dlinn [17]4 years ago
5 0

Answer:

The cost is $43.2

Step-by-step explanation:

The first thing to do here is to calculate the amount of energy consumed.

From the question, we are told that this is;

Power * Time

From the question, power = 1600 watts

Time = 9 hours

So amount of energy consumed = 1600 watts * 9 hours = 14,400 watts hour

It should be known that energy is measured in Kilowatts hour ; So therefore 14,440 watts hour is 14,440/1000 kwh = 14.4 kwh

Now, the cost per unit of energy is $3.00 per kwh

So the cost of using 14,400 watts hour would be 14.4 * 3 = $43.2

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Solve ninety two hundredths plus four and six tenths plus eight
stiks02 [169]
13.52 should be the correct answer
8 0
4 years ago
5. Use any method to solve the equation. If necessary, round to the nearest hundredth.
DanielleElmas [232]

Answer:

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Step-by-step explanation:

Since the equation has only one term in the unknown "x", we can solve for it isolating "x" on one side of the equal sign:

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Which we can round to: x = - 2.45 and x = 2.45

7 0
4 years ago
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emmasim [6.3K]

Answer:

0.216

Step-by-step explanation:

8 \times 1 \times 3 \times 0.1 \times 9 \times 0.01\\\\=(8\times1)(3\times0.1)(9\times0.01)\\\\=8(0.3)(0.09)\\\\=(8\times0.3)(0.09)\\\\=(2.4)(0.09)\\\\=2.4\times0.09\\\\=0.216

is this the standard form?

5 0
3 years ago
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Gekata [30.6K]

Answer:

1. C-surface area

2. The formula V = B x h is not suitable, because the surface area of wrapping paper needed to be calculated, not the volume.

V = Ph + 2B = 15x(5+6+9) + 2x 9x3/2 = 327

3. B: Base area

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