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AURORKA [14]
3 years ago
12

A sector of a circle has a central angle of 60°. find the area of the sector if the radius of the circle is 6 mi.

Mathematics
1 answer:
professor190 [17]3 years ago
8 0
The entire circle has a central angle of 360°.
Because the radius is 6 mi, the area of the circle is
π(6)² = 36π mi².

The sector has a central angle of 60°, therefore it occupies 60/360 = 1/6 of the area of the circle.
The area of the sector is
(1/6)*36π = 6π mi² = 18.85 mi²

Answer: 6π mi²  or  18.85 mi².

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Rosa earns $12 per hour. In 7.5 hours, she will earn x dollars. Which is a valid proportion that can be used to solve the proble
Tamiku [17]

Answer:

StartFraction x over 7.5 EndFraction = StartFraction 12 over 1 EndFraction

Step-by-step explanation:

Here, in this question, given that Rosa earns $12 in an hour, she earns x dollars in 7.5 hours. So we are interested in finding the value of x.

Let’s write this in terms of proportion;

$12 = 1 hour

$x = 7.5 hours

$12 * 7.5 hours = $x * 1 hour

So this can be rewritten as;

$x/7.5 = $12/1 hour

5 0
3 years ago
Read 2 more answers
Simplify 2√2-√3<br> ---------------<br> √2+√3
serious [3.7K]

Step-by-step explanation:

=  \frac{2 \sqrt{2}   -  \sqrt{3} }{ \sqrt{2} +  \sqrt{3}  }

=  \frac{2 \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} +  \sqrt{3}  }  \times  \frac{ \sqrt{2} -  \sqrt{3}  }{ \sqrt{2} -  \sqrt{3}  }

= \frac{ 2( \sqrt{2}  -  \sqrt{3} )( \sqrt{2}  -  \sqrt{3} )}{ { \sqrt{2} }^{2} -  { \sqrt{3} }^{2}  }

=  \frac{2(2 -  \sqrt{6}  -  \sqrt{6} - 3) }{2 - 3}

=  \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}

=  \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}

= 2(1 + 2 \sqrt{6} )

= 2 + 4 \sqrt{6}

6 0
2 years ago
PLZZ HELP <br> 2/3 divided by 5
melamori03 [73]

Answer:

2/15

Step-by-step explanation:

2/3 divided 5 is really just:

2/3*1/5

that is just 2/15!

7 0
3 years ago
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Are they unique more than one or no triangle
Tanya [424]
The measures of the angles of a triangle add to 180.

45 + 45 + 90 = 180
The measures of these three angles do add to 180, ,so there is at least one triangle with these angle measures.
Using AA triangle similarity, any triangle with the same angle measures will be similar.

From the figure you already see two triangles with angles 45-45-90. There is an infinite number of triangles with those angle measures.
8 0
3 years ago
• Use whichever method you prefer (the area model or the distributive property)
kolbaska11 [484]

Answer: 2a^2+22a+−1

Step-by-step explanation:

Let's simplify step-by-step.

2a^2−5a+(9)(3)a−1

=2a^2+−5a+27a+−1

Combine Like Terms:

=2a^2+−5a+27a+−1

=(2a^2)+(−5a+27a)+(−1)

=2a^2+22a+−1

4 0
3 years ago
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