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lutik1710 [3]
4 years ago
13

You are traveling to Chicago for a job interview. You leave Toledo, Ohio, at 5:45 A.M. and arrive in Elkhart, Indiana, at 8:15 A

.M.. The distance from Toledo to Elkhart is 136 miles; the distance from Toledo to Chicago is 244 miles. The speed limit is 65 mph. What is the minimum speed you must maintain in order to arrive in Chicago before 10:30 A.M.
Mathematics
1 answer:
baherus [9]4 years ago
4 0
The minimum speed will be calculated as follows:
Time taken from Toledo to Elkhart=(8.15-5.45)=2 1/2 hours
Distance=136 miles
thus the speed between Toledo and Elkhart= 136 miles/2.5=54.4 mph

Distance between Toledo and Chicago is 244 miles
Distance between Elkhart and Chicago=244-136=108 miles
time taken to travel between Elkhart and Chicago assuming that I left Elkhart at exactly 8:15 and reach at 10.30:
=10:30-8:15=2.25 hours
thus the speed will be:
speed=(108)/(2.25)=48 mph
Thus for us to get to Chicago by 10:30 a.m we should drive at 48 mph
 

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Answer:

25 miles, and the cost will be $37.50.

Step-by-step explanation:

Mose's charge can be represented by f(x) = 0.5x + 25, Holly's charge can be represented by g(x) = 0.3x + 30.

Set the equations equal to each other: 0.5x + 25 = 0.3x + 30.

0.2x = 5

x = 25

Substitute 25 for x: f(x) = 0.5(25) + 25 = 37.5, g(x) = 0.3(25) + 30 = 37.5.

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Which results only in a horizontal compression of Y = by a factor of 6?
elena55 [62]

Answer:

Y = 6*y

Step-by-step explanation:

We have Y = b * y by a factor of 6.

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now, to find what results only in a horizontal compression of y = b * y by a factor of 6.

By transformation rule, the function would be a horizontal compression f (a * x) if a> 1.

Therefore, knowing the above, the answer would be:

Y = 6 * y

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3 years ago
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<h3>Answers:</h3>

14.  Each leg is   21\sqrt{2}  units long.

15 (a). The longer leg is 7\sqrt{3}  units long

15 (b). The hypotenuse is 14 units long

=====================================================

Explanations:

For a 45 degree right triangle, aka 45-45-90 triangle, the hypotenuse is equal to sqrt(2) times the short leg. Algebraically we can say

y = x\sqrt{2} where x is the leg and y is the hypotenuse

Let's solve for x

y = x\sqrt{2}\\\\x\sqrt{2} = y\\\\x = \frac{y}{\sqrt{2}}\\\\x = \frac{y\sqrt{2}}{\sqrt{2}*\sqrt{2}} \ \text{rationalizing denominator}\\\\x = \frac{y\sqrt{2}}{2}\\\\

Now plug in the given hypotenuse y = 42, this leads to,

x = \frac{y\sqrt{2}}{2}\\\\x = \frac{42\sqrt{2}}{2}\\\\x = \frac{42}{2}\sqrt{2}\\\\x = 21\sqrt{2}\\\\

---------------------------

For a 30-60-90 triangle, the hypotenuse is double that of the short leg. So the hypotenuse is 2*7 = 14.

The longer leg is equal to sqrt(3) times the short leg. The longer leg is 7\sqrt{3}

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3 years ago
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It is a function, because they do not have a repeating number in the “Y” place (x,Y). If a set of orderd pairs had the y repeating, then it is not a function. The x can repeat, just not the y.
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