What is the location of the ordered pair (-3,2) on the coordinate plane

Mathematics

2 answers:

inn [45]3 years ago

7 0

You have to go 3 squares to the left (staying in the x coordinate of 0) and after that you go 2 squares up. Hope this helps. :)

Ber [7]3 years ago

5 0

Let me draw it for you.

It would look like this.

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Q8 Q3.) Solve the system by the substitution method.

inn [45]

Recall that $(x+y)^2=x^2+2xy+y^2$ . So we can add twice the first equation to the second one to get

$x^2+y^2+2xy=10+2\cdot3\iff(x+y)^2=16\implies x+y=\pm4$

Since $xy=3$ , we have $y=\dfrac3x$ $(x\neq0)$ so

$x+y=x+\dfrac3x=\pm4\implies x^2\mp4x+3=0$

If $x+y=4$ , then

$x^2-4x+3=(x-3)(x-1)=0\implies x=3,x=1\implies y=1,y=3$

If $x+y=-4$ , then

$x^2+4x+3=(x+1)(x+3)=0\implies x=-1,x=-3\implies y=-3,y=-1$

So the solution set is

$(x,y)\in\{(-3,1),(1,3),(-1,-3),(-3,-1)\}$

3 0

3 years ago

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drek231 [11]

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3 years ago

7x+2y=3 and x-3y=30, what is the value of y?

Blizzard [7]

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