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algol13
3 years ago
12

After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6, 3), B'(-2, 1),

Mathematics
2 answers:
vitfil [10]3 years ago
5 0

Answer:

A: (3, -6)

B: (1, 2)

C: (7, -1)

Step-by-step explanation:Just got it right!

Rasek [7]3 years ago
3 0

Answer:

<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)

Step-by-step explanation:

To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:

Extended Rotation Rules

  • 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
  • 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
  • 180°-rotation >> (x, y) → (-x, -y)

So, perform your rotation:

270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]

→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]

→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]

I am joyous to assist you anytime.

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Let u = &lt;-9, 4&gt;, v = &lt;8, -5&gt;. Find u - v. <br> URGENT
Pie

To subtract vectors, you simply have to subtract correspondent coordinates.

So, if you have

u = \langle u_1,\ u_2,\ldots u_n\rangle ,\quad v = \langle v_1,\ v_2,\ldots v_n\rangle

the subtraction is simply

u-v = \langle u_1-v_1,\ u_2-v_2,\ldots u_n-v_n\rangle

So, in your case, we have

\langle-9,4\rangle-\langle 8,-5\rangle=\langle -9-8, 4+5\rangle=\langle -17,9\rangle

3 0
3 years ago
The floor of a drawing room consists of 2000 tiles. Each of the tiles is rectangular in
wlad13 [49]

Step-by-step explanation:

<h2><u>☼︎</u><u>Given :</u></h2>

  • The floor of a drawing room consist of 2000 tiles .Each tiles is rectangular in shape , of dimensions ,30 cm × 20 cm.

\rule{200pt}{3pt}

<h2><u>☼︎</u><u>To Find :</u></h2>

  • Area of the room.

\rule{200pt}{3pt}

<h2><u>☼︎</u><u>Solution :</u></h2>

<u>~ Formula </u><u>U</u><u>s</u><u>e</u><u>d</u><u>:</u>

\large{\blue{\bigstar}} \: \: {\underline{\boxed{\pink{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}} \: \: {\blue{\bigstar}}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

<u>~ Calculating the</u><u> Area of Tiles </u>

{➙ \: {\sf{ Area = Length \times Breadth}}}

{➙ \: {\sf{ Area = 30 \times 20 }}}

{\sf{➙ \: Area \:  of  \: 1 Tiles = {\purple{\bf{ 600 \: cm² }}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━}

<u>~ Calculating Area of the </u><u>Drawing Room :</u>

{➙ \: {\sf{ Area \: of \: Room \: = No. \: of \: Tiles \times Area \: of \: 1 \: Tile }}}

{➙ \: {\sf{ Area \: of \: Room \: = 2000 \times 600 }}}

{\qquad{\sf{ Area \: of \: Room \: = {\color{darkblue}{\bf{ 1200000 \: cm² }}}}}}

\qquad{━━━━━━━━━━━━━━━━━━━━━}

<u>~ Therefore :</u>

❝ Area of the Drawing room is 1200000 cm² or 12000 m² . ❞

\begin{gathered} \\ {\blue{\underline{\red{\rule{300pt}{9pt}}}}}\end{gathered}

8 0
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Answer:

D. (bottom right)

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7 0
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