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Paha777 [63]
3 years ago
9

Simplify the expression. Write your answer as a power. 8^10⋅8^4

Mathematics
2 answers:
Ksivusya [100]3 years ago
4 0

Hello Tim!

8^1^0*8^4

First you had to used apply exponent rule.

8^1^0*8^4=8^1^0^+^4=8^1^4

=8^1^4

Answer⇒⇒⇒8¹⁴

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

topjm [15]3 years ago
3 0

8^14 is the answer.

This is because since they both have the same base, the exponents could be added together if the numbers are multiplied together

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Let the youngest sister be n years
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So, the equation looks like this:
n + 2n + 2(2n-2) = 45
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7n - 4 = 45
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8 0
3 years ago
Find the precent of change of 15 yards to 18 yards
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Divide the current with the previous
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5 0
3 years ago
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Suppose you school costs for this term were $4640 and financial aid covered 4/5 of that amount?
Salsk061 [2.6K]

Answer:

Covered: $3712

Still need to pay: $928

Step-by-step explanation:

4/5 --> 0.8 --> 80%

4640 x 0.8 --> 3712

Covered: $3712 (which is 80%)

Still need to pay: $928 (which is 20%)

3 0
2 years ago
Pennsylvania Refining Company is studying the relationship between the pump price of gasoline and the number of gallons sold. Fo
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Complete Question

Pennsylvania Refining Company is studying the relationship between the pump price of gasoline and the number of gallons sold. For a sample of 14 stations last Tuesday, the correlation was 0.65.At the 0.01 significance level Can the company conclude that the correlation is positive

Answer:

Yes the company conclude that the correlation is positive

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  14

    The correlation is  r =  0.65

     

The  null hypothesis is  H_o :  r <  0

The  alternative hypothesis is  H_1 :  r > 0

Generally the standard deviation is mathematically evaluated as

       Sr =  \sqrt{1- r}

       Sr =  \sqrt{1- 0.65}

       Sr = 0.616

The  degree of freedom for the one-tail test is

       df =  n- 2

        df =  14- 2

        df = 12

The standard error is evaluated as

        SE  =  \frac{0.616}{ \sqrt{12} }

        SE  =0.1779

The test statistics  is evaluated as

      t =  \frac{r }{SE}

       t =  \frac{0.65 }{0.1779}

        t =  3.654

The p-value of of  t is obtained from the z table, the value is  

        p-value =  P(t <  3.654) =  0.00012909

Given that p-value  <  \alpha  then we reject the null hypothesis

           Hence the company can conclude that the correlation is positive

     

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3 years ago
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Mariana [72]

Answer:

approximately 4 days... but ummm  the 26 is a tuesday...

Step-by-step explanation:

5 0
3 years ago
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