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Zepler [3.9K]
3 years ago
13

Sherwood has a square flower garden

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

9 times

Step-by-step explanation:

3 × 3 = 9

172 ÷ 9 = 9 and 1/9

so she can only fertilize the garden 9 times

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An athlete training for the olympics swims each lap of a four-lap race in the following times: 54.73 , 54.56 , 54.32 , and 54.54
solniwko [45]

Answer:

218.25 seconds

Step-by-step explanation:

54.73

54.56

54.32

54.54

+_____

218.15

3 0
3 years ago
Which expression is equivalent to<br>the answer are after the first one
seraphim [82]
It would be D)
Hope this helps
5 0
3 years ago
Select all the correct answers.
irina1246 [14]

Operations that can be applied to a matrix in the process of Gauss Jordan elimination are :

replacing the row with twice that row

replacing a row with the sum of that row and another row

swapping rows

Step-by-step explanation:

Gauss-Jordan Elimination is a matrix based way used to solve linear equations or to find inverse of a matrix.

The elimentary row(or column) operations that can be used are:

1. Swap any two rows(or colums)

2. Add or subtract scalar multiple of one row(column) to another row(column)

as is done in replacing a row with sum of that row and another row.

3. Multiply any row (or column) entirely by a non zero scalar as is done in replacing the row with twice the row, here scalar used = 2

6 0
3 years ago
Order from least to greatest 52,701, 54,025, 5, 206
andre [41]

First: 5.

Second: 206.

Third: 52,701.

Fourth: 54,025.

5 0
3 years ago
Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 + y2 = 25 and the sphere x2 + y2
Inessa05 [86]

Answer:

Step-by-step explanation:

we are asked to find the volume of solid that lies within both the cylinder

x^2 + y^2 = 25

and

the spherex^2 + y^2 + z^2 = 49.

Conversion from rectangular to cylindrical is

x=rcost\\y = rsint\\z=z

|J| =r

In cylindrical coordinates the volume is bounded by the cylinder r=5 and

r^2+z^2 =49

Hence we can write volume as

\int \int \int dxdydz\\=\\\int _0^5 \int_0^{2\pi} \int_{-\sqrt{49-r^2} } ^{\sqrt{49-r^2} rdzdtdr\\= 2\pi \int _0^5 (2\sqrt{49-r^2} rdr\\=4\pi (-(49-r^2) (2/3)\\= \frac{4\pi}{3} (343-48\sqrt{6} )

6 0
3 years ago
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