f(x) = (x - 2)^3 + 1
Find the derivative:-
f'(x) = 3(x -2)^2 This = 0 at the turning points:-
so 3(x - 2)^2 =
giving x = 2 . When x = 2 f(x) = 3(2-2)^3 + 1 = 1
Answer is (2, 1)
Answer:
(a) 5
(b) 3rd quartile
(c) 2nd quartile
Step-by-step explanation:
There are four quartiles in a box plot <em>(or box and whisker plot).</em>
The 1st is from 5 to 13
The 2nd is from 13 to 35
The 3rd is from 35 to 40
The 4th is from 40 to 48
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(a) The lowest that this box plot goes is 5 <em>(between the 4 and 6)</em>
(b) 3rd quartile — we can see that the left and right borders are close together, meaning that the data values for this quartile are close together, and therefore concentrated
(c) 2nd quartile — we can see that this quartile is the widest, and therefore the data values are spread out
Answer:
D 80
Step-by-step explanation:
step by step
350 +(-350)=0 + 5h = 750 + (-350) =400
5h/5 =400/5=80
h=80
first, find the numeric value for 11/15
second to find theta, simply do the <em>inverse</em> cos (which is cos^-1) of the first answer.
now you know theta, just do the sin of 90 - theta and that's it!
since you know whatr cos(theta) is, you just take the inverse cos of that number to get theta and 'reverse' cos, essentially. you are just solving for theta, by reversing the cos function with cos^-1
please mark as brainliest!
You would have to make a point at 6/3 and go down one and to the left 7... then your answer would be -1/2 sooo D=-1 hope this helps
