Split up the interval [0, 2] into 4 subintervals, so that
Each subinterval has width . The area of the trapezoid constructed on each subinterval is , i.e. the average of the values of at both endpoints of the subinterval times 1/2 over each subinterval .
So,
3x+3 + 10x-4 +90 (because complementary angle add up to 90)
13x-1+90 (add 1)
13x/13=91 (divide 13 on both sides)
x=7
now you fill in 7 for x
m<K=24 and m<L=66
hope i helped
The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
Read more about inverse functions at:
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x is the variable
<em>In mathematics, a variable is a symbol; in this case, X.</em>
Answer: 7
Step by Step explanation: