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Amanda [17]
3 years ago
7

What are the solutions of x^2+6x-6=10

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
4 0
X^2 +6x-6=0 taking  -6  to  cross  the  equal sign 

x^2+6x=6 by  completing squ.
 x^2 +6x+ 9= 6+9
x^2 +6x +9 =15
(x+3)^2= 15
x+3= 15^0.5
x= 3,87298-3 or -3.87298-3
x= 0.87298 or -6.87298

sergejj [24]3 years ago
3 0

Answer: I think its -8 and 2

Step-by-step explanation:

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Anton bought a picnic cooler. His total bill, with tax, was $7.95. He paid 6 percent sales tax. How much did he pay for the cool
Rus_ich [418]
7.95 ÷ 1.06 = $7.50

This works as by dividing 7.95 by the percentage multiplier 1.06 it will give you the original amount.

An alternative method is to find out what 100% (7.95) is, then divide by 10 to find 10% and then divide by 10 again to find 1% and then multiply the 1% by 6 and subtracting the answer from 7.95.
7 0
3 years ago
louise bought 80 metres of fencing to make an enclosure for her pet dog .tommy if louise expects a rectangular enclosure what is
OleMash [197]

Answer:

400 m^2.

Step-by-step explanation:

The largest  area is obtained where the enclosure is a square.

I think that's the right answer because a square is a special form of a rectangle.

So the square would be 20 * 20  = 400 m^2.

Proof:

Let the  sides of the rectangle be x and y m long

The area A = xy.

Also the perimeter  2x + 2y = 80

x + y = 40

y = 40 - x.

So substituting for y in A = xy:-

A = x(40 - x)

A = 40x - x^2

For maximum value of A  we find the derivative and equate it to 0:

derivative A' =  40 - 2x = 0

2x = 40

x = 20.

So y = 40 - x

= 40 - 20

=20  

x and y are the same value so x = y.

Therefore for maximum area the rectangle is a square.

3 0
3 years ago
18. Brown eyes (B) are dominant to blue eyes (b). The presence of freckles (F) is dominant to the absence of freckles (f). What
MrRissso [65]

Answer:

For bbff we have only 6.3% probability

Step-by-step explanation:

If the parents are heterozygous for both traits, them they are represented by:

BbFf × BbFf

Parent 1: BbFf

Parent 2: BbFf

We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.

By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:

Genotype   Count     Percent  

bBfF  4     25

BBfF  2     12.5

bBFF  2     12.5

bBff          2     12.5

bbfF  2     12.5

BBFF  1     6.3

BBff      1            6.3

bbFF  1     6.3

bbff      1     6.3

For bbff we have only 6.3% probability

6 0
3 years ago
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kompoz [17]

Answer:

yes

Step-by-step explanation:

8 0
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Answer:

Solution given:

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8 0
3 years ago
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