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1 answer:
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Part 1:
Let x represent orders of fries and y represent burgers, then the <span>system of equations that models the given situation is given by:
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Part 2:
The graph of the two equations is attached.
From the graph it can be seen that the point of intersection of the lines representing the two equations is at point (2, 3), i.e. x = 2, y = 3.
Therefore, each order of fries costs $2 while each order of burger costs $3.
Part 3:
Using elimination, first we make the coefficients of y in both equations by multiplying the second equation by 2 and then subtracting the result from the first equation.
i.e.
equation (2) x 2 gives:
</span>
.
Subtracting from equation (1), we have:
Now, from the second equation,
Thus, x = 2 and y = 3.
Therefore, each order of fries costs $2 while each order of burger costs $3.
Let x represent orders of fries and y represent burgers, then the <span>system of equations that models the given situation is given by:
</span>
<span>
Part 2:
The graph of the two equations is attached.
From the graph it can be seen that the point of intersection of the lines representing the two equations is at point (2, 3), i.e. x = 2, y = 3.
Therefore, each order of fries costs $2 while each order of burger costs $3.
Part 3:
Using elimination, first we make the coefficients of y in both equations by multiplying the second equation by 2 and then subtracting the result from the first equation.
i.e.
equation (2) x 2 gives:
</span>
Subtracting from equation (1), we have:
Now, from the second equation,
Thus, x = 2 and y = 3.
Therefore, each order of fries costs $2 while each order of burger costs $3.