they both have the same denominators (number at the bottom of the fraction) so all you have to do it subtract the numerators (top of the fraction) together. 2x-x =x, that's why it's x on the numerator for the answer

hope this helps

4 0

2 years ago

Read 2 more answers

An investment website can tell what devices are used to access their site. The site managers wonder whether they should enhance

lbvjy [14]

Answer: a) Unimodal and symmetric

b) 0.26

c) 0.038

Step-by-step explanation:

Given: Sample size of investors (n)= 131

True proportion of smartphone users(p) =26%

a) Since sampling distribution for the sample proportion is approximately normal when n is larger.

Normal distribution is Unimodal and symmetric.

So correct option : Unimodal and symmetric

b) mean of this sampling distribution = p = 0.26

c) standard deviation of the samplingdistribution = $\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26\times (1-0.26)}{131}}=\sqrt{0.00146870229008}$

$=0.0383236518364\approx0.038$

6 0

2 years ago

If the area of the square is A(s) = s², find the formula for the area as a function of time, and then determine A(s(3)).

Oxana [17]

A(t) = 100t^2 + 500t + 625

3,025 square pixels

5 0

2 years ago

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A local high school has both male and female students.

Kitty [74]

Answer:

a. P(male) = 0.4

b. P(no sport and male) = 0.1

c. Unclear question (isn't it the same as b.?)

Step-by-step explanation:

The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;

$\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]$

$P(male) = \frac{7 + 21}{70} \\\\ = \frac{28}{70} \\\\ = \frac{2}{5}$

Using the tree diagram in the picture;

$P(no \ sport \ and \ male) = \frac{2}{5} * \frac{1}{4} \\\\ = \frac{1}{10}$

8 0

2 years ago