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3 years ago

15 increased by a number x

1 answer:

3 0

15 increased by a number x: 15 + x
a number x more than −14: x > -14
the difference of 7 and a number x: 7/x

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Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16

sweet-ann [11.9K]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

Given:

$2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)$

Use the Power Rule Law:

$log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)$

Use the Quotient Rule Law:

$log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})$

Use the Product Rule Law:

$log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})$

Simplify:

$log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})$

$\frac{4}{9}=\frac{8\sqrt{x}}{9}$

$4=8\sqrt{x}$

$\frac{4}{8}=\sqrt{x}$

$\frac{1}{2}=\sqrt{x}$

$\frac{1}{4}=x$

5 0

2 years ago

Hey! A step by step explanation on this would be great! Thanks! (25 Points)

kicyunya [14]

Step-by-step explanation:

We find the stationary point of (20 + 2x)(1200 - 60x),

where x is the unit rate of increase/decrease.

d/dx [(20 + 2x)(1200 - 60x)]

= d/dx (-120x² + 1200x + 24000)

= -240x + 1200.

When d/dx [(20 + 2x)(1200 - 60x)] = 0,

We have -240x + 1200 = 0. => x = 5.

Price per shirt that maximise revenue

= $20 + $2x = $20 + $2(5) = $30.

Maximum revenue

= (20 + 2(5))(1200 - 60(5))

= $30 * 900 = $27,000.

6 0

2 years ago

Please graph y=−1/2. thank you!

Dominik [7]

Answer:

There would be a straight line at -0.5 on the graph.

Step-by-step explanation:

Hope this helps

4 0

3 years ago

Jennifer is the coach for a Little League Baseball team, the Pirates. She wants to buy new t-shirts for the players. What would

mash [69]

Step-by-step explanation:

Price of one shirt =?

Six packages of three t-shirt = 6 x 3 = 18 shirts

18 shirts = 71.39

1 shirt = 71.39/18

1 shirt = 3.966 or 4

5 0

3 years ago

What is 10 to the second power?

allochka39001 [22]

It would be 10x10 =100 or in other word 10 times itself. Also known as 10 with the 2 hanging over the 10.

3 0

3 years ago

Read 2 more answers